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2020-2021:teams:alchemist:mountvoom:training1 [CVBB ACM Team]

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2020-2021:teams:alchemist:mountvoom:training1 [2020/05/13 20:24]
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2020-2021:teams:alchemist:mountvoom:training1 [2020/05/13 20:25] (当前版本)
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 当$k$很大时,假设$n - 1$操作后第$i$张牌编号为$p[i]$,那么$2(n - 1)$次操作后,第$i$张牌编号为$p[p[i]]$,这一部分可以倍增或者把排列$p$拆成循环来处理。 当$k$很大时,假设$n - 1$操作后第$i$张牌编号为$p[i]$,那么$2(n - 1)$次操作后,第$i$张牌编号为$p[p[i]]$,这一部分可以倍增或者把排列$p$拆成循环来处理。
  
-剩下的$k % (n - 1)$次直接模拟即可。+剩下的$k ​\% (n - 1)$次直接模拟即可。
 ===== J. 斐波那契和 ===== ===== J. 斐波那契和 =====
2020-2021/teams/alchemist/mountvoom/training1.1589372668.txt.gz · 最后更改: 2020/05/13 20:24 由 mountvoom