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2020-2021:teams:farmer_john:2020.8.2 [2020/08/07 14:59] 2sozx 创建 |
2020-2021:teams:farmer_john:2020.8.2 [2020/08/07 21:10] (当前版本) 2sozx [题解] |
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[[https://codeforces.com/gym/289702|比赛链接]] | [[https://codeforces.com/gym/289702|比赛链接]] | ||
- | =====CF Expected diameter of a tree===== | + | =====CF Karen and Test===== |
====题意==== | ====题意==== | ||
====题解==== | ====题解==== | ||
- | =====CF Selling Souvenirs===== | + | =====CF Karen and Supermarket===== |
====题意==== | ====题意==== | ||
====题解==== | ====题解==== | ||
- | =====CF Card Game===== | + | =====CF Choosing The Commander===== |
====题意==== | ====题意==== | ||
====题解==== | ====题解==== | ||
- | =====CF Anthem of Berland===== | + | =====CF MEX Queries===== |
====题意==== | ====题意==== | ||
====题解==== | ====题解==== | ||
- | =====CF Glad to see you!===== | + | =====CF Sofa Thief===== |
====题意==== | ====题意==== | ||
====题解==== | ====题解==== | ||
- | =====CF Vladik and Favorite Game===== | + | =====CF Level Generation===== |
====题意==== | ====题意==== | ||
+ | $q$ 次询问,每次给出一个 $n$,问 $n$ 个点最多能连几条边使得桥的个数大于等于边数的一半。 $q\le10^5,n\le2\cdot10^9$ | ||
====题解==== | ====题解==== | ||
- | =====CF Sagheer and Apple Tree===== | + | 考虑 $n$ 个点最多形成 $n-1$ 个桥,因此将 $n$ 个点顺次链接。现在考虑向其中加边,若前 $x$ 个点构成了完全图,显然之后是依次连接 $1\sim x$ 和 $x+1$ 最优,因此我们考虑 $x$ 最大为多少。 $x$ 要满足以下式子:$$sum=C(x,2)+n-x,n-x\ge \frac{ans}{2}$$合并得到 $x^2+x\le2n$,可以通过解方程 $O(1)$ 得到。接下来考虑加边,考虑桥的数量和非桥边的数量的差值 $s$,要求 $s\ge0$ ,加的第一条边会增加两条非桥边并且减少一条桥边, 即 $s=s-3$ ,之后每加一条边 $s=s-1$,因此当 $s\ge3$ 时可以增加 $s-2$ 条边 ,否则不可以加边,因此每个询问可以 $O(1)$ 计算出答案。 |
+ | =====CF Mister B and Boring Game===== | ||
====题意==== | ====题意==== | ||
====题解==== | ====题解==== | ||
- | =====CF Army Creation===== | + | =====CF Jon and Orbs===== |
====题意==== | ====题意==== | ||
====题解==== | ====题解==== | ||
- | =====CF Bipartite Checking===== | + | =====CF Broken robot1===== |
====题意==== | ====题意==== | ||
====题解==== | ====题解==== | ||
- | =====CF An overnight dance in discotheque===== | + | =====CF Okabe and City===== |
====题意==== | ====题意==== | ||
====题解==== | ====题解==== |