这里会显示出您选择的修订版和当前版本之间的差别。
两侧同时换到之前的修订记录 前一修订版 后一修订版 | 前一修订版 | ||
2020-2021:teams:farmer_john:jjleo:2020.05.16-2020.05.22 [2020/05/22 22:16] jjleo [CF979D] |
2020-2021:teams:farmer_john:jjleo:2020.05.16-2020.05.22 [2020/06/25 23:06] (当前版本) jjleo ↷ 页面2020-2021:teams:farmer_john:2020.05.16-2020.05.22被移动至2020-2021:teams:farmer_john:jjleo:2020.05.16-2020.05.22 |
||
---|---|---|---|
行 430: | 行 430: | ||
}</code></hidden> | }</code></hidden> | ||
=====CF1093G===== | =====CF1093G===== | ||
- | <hidden><code cpp></code></hidden> | + | 高维曼哈顿距离+线段树。 |
+ | <hidden><code cpp>#include <bits/stdc++.h> | ||
+ | #define maxn 200086 | ||
+ | using namespace std; | ||
+ | |||
+ | struct Node{ | ||
+ | int sum[32]; | ||
+ | |||
+ | Node(){ | ||
+ | memset(sum, -0x3f, sizeof(sum)); | ||
+ | } | ||
+ | |||
+ | inline int & operator [] (int i){ | ||
+ | return sum[i]; | ||
+ | } | ||
+ | |||
+ | }t[maxn << 2]; | ||
+ | |||
+ | |||
+ | #define ls(x) (x << 1) | ||
+ | #define rs(x) (x << 1 | 1) | ||
+ | |||
+ | inline void up(int x){ | ||
+ | for(int i = 0;i < 32;i++) t[x][i] = max(t[ls(x)][i], t[rs(x)][i]); | ||
+ | } | ||
+ | |||
+ | void modify(int x, int l, int r, int pos, Node d){ | ||
+ | if(l == r){ | ||
+ | t[x] = d; | ||
+ | return; | ||
+ | } | ||
+ | int mid = l + r >> 1; | ||
+ | if(mid >= pos) modify(ls(x), l, mid, pos, d); | ||
+ | else modify(rs(x), mid + 1, r, pos, d); | ||
+ | up(x); | ||
+ | } | ||
+ | |||
+ | Node query(int x, int l, int r, int ll, int rr){ | ||
+ | if(ll <= l && r <= rr) return t[x]; | ||
+ | int mid = l + r >> 1; | ||
+ | Node a, b; | ||
+ | if(mid >= ll){ | ||
+ | b = query(ls(x), l, mid, ll, rr); | ||
+ | for(int i = 0;i < 32;i++) a[i] = max(a[i], b[i]); | ||
+ | } | ||
+ | if(mid < rr){ | ||
+ | b = query(rs(x), mid + 1, r, ll, rr); | ||
+ | for(int i = 0;i < 32;i++) a[i] = max(a[i], b[i]); | ||
+ | } | ||
+ | return a; | ||
+ | } | ||
+ | |||
+ | int n, k, x, y; | ||
+ | int q, opt; | ||
+ | Node a; | ||
+ | |||
+ | |||
+ | int main(){ | ||
+ | scanf("%d%d", &n, &k); | ||
+ | for(int i = 1;i <= n;i++){ | ||
+ | memset(a.sum, 0, sizeof(a.sum)); | ||
+ | for(int j = 0;j < k;j++){ | ||
+ | scanf("%d", &x); | ||
+ | for(int l = 0;l < 32;l++){ | ||
+ | if(l & (1 << j)) a[l] += x; | ||
+ | else a[l] -= x; | ||
+ | } | ||
+ | } | ||
+ | modify(1, 1, n, i, a); | ||
+ | } | ||
+ | scanf("%d", &q); | ||
+ | while(q--){ | ||
+ | scanf("%d", &opt); | ||
+ | if(opt == 1){ | ||
+ | int i; | ||
+ | scanf("%d", &i); | ||
+ | memset(a.sum, 0, sizeof(a.sum)); | ||
+ | for(int j = 0;j < k;j++){ | ||
+ | scanf("%d", &x); | ||
+ | for(int l = 0;l < 32;l++){ | ||
+ | if(l & (1 << j)) a[l] += x; | ||
+ | else a[l] -= x; | ||
+ | } | ||
+ | } | ||
+ | modify(1, 1, n, i, a); | ||
+ | }else{ | ||
+ | scanf("%d%d", &x, &y); | ||
+ | a = query(1, 1, n, x, y); | ||
+ | int ans = -1e9; | ||
+ | for(int i = 0;i < (1 << k);i++) ans = max(ans, a[i] + a[(1 << k) - 1 - i]); | ||
+ | printf("%d\n", ans); | ||
+ | } | ||
+ | } | ||
+ | }</code></hidden> |