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2020_multi-university_training_contest_10
2020-2021:teams:mian:nowcoder_training:2020_multi-university_training_contest_10
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====== 2020牛客暑期多校训练营(第十场) ====== ===== Results ===== ==== Summary ==== * Solved 7 out of 12 problems * Rank 32/1041 in official records * Solved 8 out of 12 afterwards <HTML> <table> <style> td, th {text-align: center;} .accepted {color: #0a0;font-weight: bold;} .failed {color: #00a;} .cell-time {font-size: 1.0rem;display: block;} .contest-name {font-size: 1.5em;color: #445f9d;} .successfulChallengeCount {color: green;} .unsuccessfulChallengeCount {color: gray;} </style> <tr><th>#</th><th>Who</th><th>=</th><th>Penalty</th><th>A</th><th>B</th><th>C</th><th>D</th><th>E</th><th>F</th><th>G</th><th>H</th><th>I</th><th>J</th><th>Dirt</th></tr> <tr><td>11</td><td>大吉大利,今晚吃 mian();</td><td>3</td><td>534</td><td><span class="accepted">+1</span><br>02:01</td><td></td><td></td><td></td><td><span class="accepted">+1</span><br>01:07</td><td></td><td></td><td><span class="failed">-2</span></td><td><span class="failed">-3</span></td><td><span class="accepted">+2</span><br>04:26</td><td><span><b>57%</b></span><br>4/7</td></tr></table> </HTML> ==== Member Distribution ==== ^ Solved ^ A ^ B ^ C ^ D ^ E ^ F ^ G ^ H ^ I ^ J ^ | Pantw | | | | | | | | | | √ | | Withinlover | | | | | √ | | | | | | | Gary | √ | | | | | | | | | | (√ for solved, O for upsolved, - for tried but not solved) ---- ====== Solutions ====== ===== A ===== 半天也没搞懂怎么证得,尽量选2,不能选2就选一次3 ===== B ===== ===== C ===== ===== D ===== ===== E ===== 二分然后暴力从后往前推就好了 ===== F ===== ===== G ===== ===== H ===== ===== I ===== ===== J ===== 考虑 DP。对每个结点,考虑其所有儿子的子树,算出它们与对应点的儿子的子树的权值 G[i][j],算出来之后把它们建成二分图,再直接在二分图上跑一个最小费用最大流即可。 ------------- ====== Comments ====== ptw: * 抢榆枋而止 Gary: * C题思路上有问题,平常都是类似题解的方式讨论,今天脑子抽了 * 在一次提醒自己写板子 Withinlover: * 注 意 肠 道 卫 生 * 现在看E题挺显然的不知道自己当时在懵啥(
2020-2021/teams/mian/nowcoder_training/2020_multi-university_training_contest_10.txt
· 最后更改: 2020/08/12 15:43 由
withinlover
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