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C D (D题 好题！k1i=k2j,若k1为奇数，k2为偶数，则形成一个奇环 即 i/gcd(i,j)为奇数，j/gcd(i,j)为偶数 即i=2x1奇数，j=2x2奇数，若 x1!=x2,则i/gcd(i,j),j/gcd(i,j)为一奇一偶，形成奇环，所以只有阶数相同的才能不构成奇环，且全是奇数组合之后，也不会有偶环。 E E 题 思维，实现方式好！