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2020-2021:teams:mian:nowcoder_training:2020_multi-university_training_contest_10

这是本文档旧的修订版!


2020牛客暑期多校训练营(第十场)

Results

Summary

  • Solved 7 out of 12 problems
  • Rank 32/1041 in official records
  • Solved 8 out of 12 afterwards
#Who=PenaltyABCDEFGHIJDirt
11大吉大利,今晚吃 mian();3534+1
02:01
+1
01:07
-2-3+2
04:26
57%
4/7

Member Distribution

Solved A B C D E F G H I J
Pantw
Withinlover
Gary

(√ for solved, O for upsolved, - for tried but not solved)


Solutions

A

B

C

D

E

F

G

H

I

J

考虑 DP。对每个结点,考虑其所有儿子的子树,算出它们与对应点的儿子的子树的权值 G[i][j],算出来之后把它们建成二分图,再直接在二分图上跑一个最小费用最大流即可。


Comments

ptw:

  • 抢榆枋而止
2020-2021/teams/mian/nowcoder_training/2020_multi-university_training_contest_10.1597062930.txt.gz · 最后更改: 2020/08/10 20:35 由 grapelemonade