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        <title>CVBB ACM Team 2020-2021:teams:farmer_john:2sozx:数学</title>
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       <dc:date>2026-04-30T02:34:00+0800</dc:date>
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        <title>CVBB ACM Team</title>
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        <dc:date>2020-05-09T20:37:37+0800</dc:date>
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        <title>2020-2021:teams:farmer_john:2sozx:数学:一道没有来源的题目</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:farmer_john:2sozx:%E6%95%B0%E5%AD%A6:%E4%B8%80%E9%81%93%E6%B2%A1%E6%9C%89%E6%9D%A5%E6%BA%90%E7%9A%84%E9%A2%98%E7%9B%AE&amp;rev=1589027857&amp;do=diff</link>
        <description>题意

	*  平面上有$n(n{\le}8)$个点，告诉你每个点距离原点的距离,求这$n$个点所围成的凸包的最大面积

题解

	*  枚举哪些点在凸包上,并且这些点极角排序后的顺序。假设极径依次为$r_1,r_2,⋯,r_n$。
面积$S={\frac{1}{2}}(r_1r_2sinθ_1+r_2r_3sinθ_2+⋯+r_nr_1sinθ_n)$并且${\sum_{i=1}^n}{\theta}_i=2\pi$。
令$F(θ_1,θ_2,⋯,θ_n)=S+{\lambda}g(θ_1,θ_2,⋯,θ_n)$,其中$g(θ_1,θ_2,⋯,θ_n)={\sum_{i=1}^n}{\theta}_i-2\pi$$-λ=r_1r_2cosθ_1=r_2r_3cosθ_2=⋯=r_nr_1cosθ_n$$λ$$g=0$$\theta$…</description>
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        <dc:date>2020-06-12T22:13:12+0800</dc:date>
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        <title>2020-2021:teams:farmer_john:2sozx:数学:知识点</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:farmer_john:2sozx:%E6%95%B0%E5%AD%A6:%E7%9F%A5%E8%AF%86%E7%82%B9&amp;rev=1591971192&amp;do=diff</link>
        <description>格式：

	*  向量建议写成 $\boldsymbol{x}_{0}$

内容：

	*  没有例题吗

知识点

前言

对于一元函数的极值问题相信大家都十分熟悉，但是对于多元函数的极值问题可能就会比较陌生。大家都学过淑芬怎么可能陌生呢$f(\boldsymbol{x})$${\boldsymbol{\varphi}}(\boldsymbol{x})=({\varphi}_1(\boldsymbol{x}),{\varphi}_2(\boldsymbol{x}),\cdots,{\varphi}_m(\boldsymbol{x}))$$D\subset \mathbb{R}^n (m&lt;n)$${\boldsymbol{x_0}}=({x_1}^0,{x_2}^0,\cdots,{x_n}^0)\in D$$f(\boldsymbol{x})$$$\begin{cases}{\varphi}_1(\boldsymbol{x})=0 \\{\varphi}_2(\boldsymbol{x})=0 \\ \vdots\\{\varphi}_m(\boldsymbol{x})=0\end{…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2020-05-20T14:44:09+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:farmer_john:2sozx:数学:类欧几里得</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:farmer_john:2sozx:%E6%95%B0%E5%AD%A6:%E7%B1%BB%E6%AC%A7%E5%87%A0%E9%87%8C%E5%BE%97&amp;rev=1589957049&amp;do=diff</link>
        <description>占坑</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2020-05-17T21:29:22+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:farmer_john:2sozx:数学:遗留的知识点</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:farmer_john:2sozx:%E6%95%B0%E5%AD%A6:%E9%81%97%E7%95%99%E7%9A%84%E7%9F%A5%E8%AF%86%E7%82%B9&amp;rev=1589722162&amp;do=diff</link>
        <description>知识点

前言

对于一元函数的极值问题相信大家都十分熟悉，但是对于多元函数的极值问题可能就会比较陌生。大家都学过淑芬怎么可能陌生呢

对于没有限制条件的多元函数来说，只需要对函数求导即可，但是若有了限制条件，即函数的值要在一定条件下才能取到，则需要用到拉格朗日乘子法。$f(\vec{x})$${\vec{\varphi}}(\vec{x})=({\varphi}_1(\vec{x}),{\varphi}_2(\vec{x}),…,{\varphi}_m(\vec{x}))$$D\subset \mathbb{R}^n (m&lt;n)$${\vec{x_0}}=({x_1}^0,{x_2}^0,…,{x_n}^0)\in D$$f(\vec{x})$$$\begin{cases}{\varphi}_1(\vec{x})=0 \\{\varphi}_2(\vec{x})=0 \\…\\{\varphi}_m(\vec{x})=0\end{cases}$$${\varphi}'(x_0)$$m$${\lambda}_1,{\lambda}_2,…,{\lambda}_3{\in}\mathbb…</description>
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        <dc:date>2020-05-20T14:41:22+0800</dc:date>
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        <title>2020-2021:teams:farmer_john:2sozx:数学:exgcd</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:farmer_john:2sozx:%E6%95%B0%E5%AD%A6:exgcd&amp;rev=1589956882&amp;do=diff</link>
        <description>扩展欧几里得

用途

解裴蜀方程

写法

通过普通的欧几里得算法来求解


int exgcd(int a, int b, int&amp; x, int&amp; y){
	if(!b) {y=0,x=1;return a;}
	int gcd=exgcd(b,a%b,y,x); 
	y-=a/b*x;
	return gcd;
}</description>
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