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        <title>2020-2021:teams:hotpot:aspirine:多项式对数函数</title>
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        <description>问题描述

给定一个n-1次多项式$f(x)$，保证$a_0=1$。求$\ln(f(x))$对$x^n$取模的结果。系数模998244353

$\ln(f(x))$定义为其幂级数展开，对$x^n$取模为其幂级数的前n项和。

解决方法

前置知识

多项式乘法（NTT），多项式求逆，多项式求导、积分（这个所有人都会）$g(x)=\ln(f(x))$$g'(x)\equiv\frac{f'(x)}{f(x)}\equiv f'(x)f^{-1}(x)\pmod{x^n}$$f^{-1}(x)$$x^n$$f'(x)$$f'(x)f^{-1}(x)$$g'(x)$$x^n$$g(x)$</description>
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        <dc:date>2020-07-17T15:48:10+0800</dc:date>
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        <title>2020-2021:teams:hotpot:aspirine:矩阵树定理</title>
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