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        <description>Codeforces Round #641 (Div. 2)

A.Orac and Factors

题目大意

对于一个数 $n ≤ 10^6$ ，找到它最小的不是1的约数，然后加在这个值上，重复 $k ≤ 10^9 $次

解题思路

首先对于偶数，这个数一定是 2，而对于奇数，一次操作之后就会变成偶数，答案是显然的。$ a_n  (n \le 1e6) $$a_j  &gt; a_i $$ O( nlogn ) $$ s_n (n \le 100000) $$ t = \{ lcm({a_i,a_j})|i &lt; j \} $$ gcd(t) $$ lcm,gcd $$ a_n (n \le 100000 ，1 \le a_i \le 1e9) $$k (1 \le k \le 1e9) $$ k $$ k $$ k $$ k $$ k $$ k $$ k $$ k $$\ge k$$k$$k$$k$$ n \times m 的 01 矩阵 (1 \le n,m \le 1000)$$ (0 \rightarrow 1, 1 \rightarrow 0) $$ t \le 100000…</description>
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