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        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:code1&amp;rev=1589094044&amp;do=diff</link>
        <description>#include&lt;cstring&gt;
#include&lt;cstdio&gt;
#include&lt;iostream&gt;
#include&lt;algorithm&gt;
#include&lt;vector&gt;
#include&lt;cmath&gt;
#include&lt;map&gt;
#define l(x) (x&lt;&lt;1)
#define r(x) ((x&lt;&lt;1)+1)
#define IL inline
#define reg register
#define LL long long
#define INF 0x3f3f3f3f
using namespace std;

int i,len,mod;
LL a,b;
int z[20];
LL mi[19],f[20][200][200];

IL int Abs(int x){return (x&lt;0)?-x:x;}
IL void Swap(int &amp;a,int &amp;b){a^=b^=a^=b;}
IL int Min(int a,int b){return (a&lt;b)?a:b;}
IL int Max(int a,int b){return (a&gt;b)?a:b;}

IL…</description>
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        <dc:date>2020-05-10T15:01:28+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:code2</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:code2&amp;rev=1589094088&amp;do=diff</link>
        <description>#include&lt;cstring&gt;
#include&lt;cstdio&gt;
#include&lt;iostream&gt;
#include&lt;algorithm&gt;
#include&lt;vector&gt;
#include&lt;cmath&gt;
#include&lt;map&gt;
#define l(x) (x&lt;&lt;1)
#define r(x) ((x&lt;&lt;1)+1)
#define IL inline
#define reg register
#define LL long long
#define MOD 10000007
#define INF 0x3f3f3f3f
using namespace std;

LL n,len,l;
LL z[75],f[75][75];

IL int Abs(int x){return (x&lt;0)?-x:x;}
IL void Swap(int &amp;a,int &amp;b){a^=b^=a^=b;}
IL int Min(int a,int b){return (a&lt;b)?a:b;}
IL int Max(int a,int b){return (a&gt;b)?a:b;}

IL int rea…</description>
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        <description>class Solution:
    def minWindow(self, s: str, t: str) -&gt; str:
        i, j, n, m = 0, 0, len(s), len(t)
        tot, ans = 0, (1e9, (0, -1))
        chs = {c:t.count(c) for c in t}
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                    tot += 1
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                        chs[s[i]] += 1
                        if chs[s[i]] &gt; 0:
                  …</description>
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        <dc:date>2020-05-10T15:02:43+0800</dc:date>
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        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:code4&amp;rev=1589094163&amp;do=diff</link>
        <description>#include &lt;cstdio&gt;
#include &lt;climits&gt;
#include &lt;vector&gt;
#include &lt;algorithm&gt;
#define IL inline
using namespace std;
constexpr int MN(1e6+7);

template &lt;typename vint, typename sint, typename xint = int&gt;
class STree
{
private:
	static constexpr xint ROOT = 1;
	struct Node
	{
		xint l, r;
		sint max, lza;
	} t[MN &lt;&lt; 2];
	xint ll, rr, pos;
	vint vv;
#define li i&lt;&lt;1
#define ri i&lt;&lt;1|1
#define t_mid ((t[i].l+t[i].r) &gt;&gt; 1)
#define add_v(i, v) ({t[i].max += v, t[i].lza += v;})

#define pd(i) \
	({ \
		if…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:contest_0723</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:contest_0723&amp;rev=1595573828&amp;do=diff</link>
        <description>比赛地址

Codeforces

Pro: 4/5/11

Rank: 13/19

[A] Three Servers

题意

给出$n$个物品,每一个物品有一个重量,现在要把这些物品分成三堆,使得最大堆物品的重量和与最小堆物品的重量和的差最小,求分配方案.

题解
$f[i][j][k]$$i$$j$$k$$A$$A$$c_{i}$$d_{i}$$a$$b$$i$$ac_{i}+bd_{i}$</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2020-05-08T20:39:41+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:contest_board</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:contest_board&amp;rev=1588941581&amp;do=diff</link>
        <description>比赛地址

Codeforces Gym

题解

复盘分析

总结</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:front_page&amp;rev=1599133363&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-09-03T19:42:43+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:front_page</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:front_page&amp;rev=1599133363&amp;do=diff</link>
        <description>训练

训练列表

周报

2020/05/04-2020/05/10 周报

2020/05/11-2020/05/17 周报

2020/05/18-2020/05/24 周报

2020/05/25-2020/05/31 周报

2020/06/01-2020/06/07 周报

2020/07/11-2020/07/17 周报

2020/07/18-2020/07/24 周报

2020/07/25-2020/07/31 周报

2020/08/01-2020/08/07 周报

2020/08/08-2020/08/14 周报

2020/08/15-2020/08/21 周报

2020/08/22-2020/08/28 周报

2020/08/29-2020/09/04 周报

团队技能树

Wiki模板库

模板库

多项式Wiki</description>
    </item>
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        <dc:format>text/html</dc:format>
        <dc:date>2020-07-17T11:12:18+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:niuke01</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke01&amp;rev=1594955538&amp;do=diff</link>
        <description>比赛地址

牛客OJ

Rank: 116/1116

Pro: 4/5/10

题解

[A] B-Suffix Array

题意

给出一个仅包含a和b的字符串,对于该字符串的每一个后缀,定义一个键值,键值第$i$位的值是出现在该后缀中的最后一个和第$i$位的字母相同的位置与$i$$a[i]$$i$$i$$u,v$$\frac{u}{v}$$\int_{0}^{1}(x-x^{2})^{n}dx \mod 998244353$$B(p,q)=\frac{\Gamma(p)\Gamma(q)}{\Gamma(p+q)}=\frac{(p-1)!(q-1)!}{(p+q-1)!}$</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke02&amp;rev=1594955713&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-07-17T11:15:13+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:niuke02</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke02&amp;rev=1594955713&amp;do=diff</link>
        <description>比赛地址

牛客OJ

Pro : 3/5/11

Rank: 312/1159

题解

[B] Boundary

题意

给出平面上$n$个点,找到一个过原点的圆,使得其能覆盖最多的点.

题解

因为已知原点在圆上,所以只需要枚举两个点就可以确定一个圆.枚举出所有的组合,算出共$\frac{n(n-1)}{2}$$k$$C_{Ans}^{2}=k$$O(n^{2}logn)$$1e-10$$n$$\frac{n+1}{2}$$a_{i}$$i$$a_{i}$$a_{\frac{n}{2}+i}$$n\times m$$a_{ij}=lcm(i,j)$$k \times k$$n$$m$$m&lt;n$$O(\frac{nm}{64})$</description>
    </item>
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        <dc:format>text/html</dc:format>
        <dc:date>2020-07-24T14:53:56+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:niuke03</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke03&amp;rev=1595573636&amp;do=diff</link>
        <description>2020牛客暑期多校第三场

比赛地址

牛客OJ

Pro: 8/8/12

Rank: 71/1175

[A] Clam and Fish

题意

有一片池塘,有四个状态,有/无蛤蜊,有/无鱼.有蛤蜊的时候可以做一个诱饵,有鱼的时候可以直接钓鱼.其他时间可以消耗一个诱饵钓一条鱼.求最多能钓几条鱼.$n$$m$$m$$m$$4n$$n$$p$$p_{i}!=i,p_{p_{i}}=i$$p,q$$\sum_{i=1}^{n}\frac{a_{i}-a_{i}'}{2}$$n=4,6$$n$$f[i]=Min(f[i],f[j]+2(a[i]-a[j+1])$$f[i]-2a[i+1]$$a,b$$c,d,e,f$$\frac{c}{d}-\frac{e}{f}=\frac{a}{b}$$d,f&lt;html&gt;&lt;b$$\frac{cf-ed}{df}=\frac{a}{b}$$d$$f$$c,e$$b$$b&lt;1$$n$$i$$i$$x$$x$$x$$O(mlogm)$…</description>
    </item>
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        <dc:format>text/html</dc:format>
        <dc:date>2020-07-24T14:55:13+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:niuke04</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke04&amp;rev=1595573713&amp;do=diff</link>
        <description>2020牛客暑期多校第四场

比赛地址

牛客OJ

Pro: 3/4/10

Rank: 117/1172

[B] Basic Gcd Problem

题意&amp;题解

签到题

[F] Finding the Order

题意&amp;题解

签到题

[G] Harder Gcd Problem

题意

给出一个整数$n$,要求从1到$n$中选出一些数构成两个大小相同的集合,且集合的元素可以两两配对,每一对的gcd大于1.求集合最大是多少.$\frac{n}{2}$$p$$2p$$n$$m$$\frac{1}{S}$</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2020-07-30T15:38:43+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:niuke05</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke05&amp;rev=1596094723&amp;do=diff</link>
        <description>2020牛客暑期多校第五场

比赛地址

牛客OJ

Pro: 5/5/11

Rank: 56/1116

[B] Graph

题意

给出一棵树,每条边有一个非负边权.有两种操作,一种是添加一条边,如果构成了一个环的话,要求这个环的边权异或值为0;第二种操作是删除一条边,但是要保证删除后图仍然连通.$O(n^2logn)$$n$$O(30nlogn)$</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke06&amp;rev=1596094794&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-07-30T15:39:54+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:niuke06</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke06&amp;rev=1596094794&amp;do=diff</link>
        <description>2020牛客暑期多校第六场

比赛地址

牛客OJ

Pro: 6/7/11

Rank: 57/1019

[A] African Sort

题意

给一个排列p,每次可以选一个下标集合进行等概率打乱并花费集合大小的代价,求将p变成升序所需的最小代价的期望.$ans_{n}=\sum_{i=2}^{n-1}\frac{ans_{i}}{i}+n$$n$$n$$f_{n}=\frac{2f_{n-1}+(2^{n}-1)}{2^{2n-1}}$$n\times n$$k$$1$$n$$A&lt;html&gt;&lt;B$$d(A)&gt;&lt;/html&gt;d(B)$$d(x)$$x$$k$$1$$k$$n$$i$$i$$i+k-1$$i+k$$i+2k-1$$1$$k$$2^{64}$$\frac{1}{2^{64}}$</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke07&amp;rev=1596790313&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-08-07T16:51:53+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:niuke07</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke07&amp;rev=1596790313&amp;do=diff</link>
        <description>2020牛客暑期多校第七场

比赛地址

牛客OJ

Pro: 4/6/11

Rank: 119/1090

[A] Social Distancing

题意

在半径为$r$的圆形区域内(含边界)放置$n$个人,要求每个人都必须在整点上,且要使$\sum_{i=1}^{n-1}\sum_{j=i+1}^{n}d(i,j)$最小.$d(i,j)$表示两个人间的欧氏距离.求这个最小值.$n\times m$$k$$k$$n$$m$$m$$n$$n&gt;m$$m$$n$$m$$m$$n\%m$$m$$n$$n\%m$$m$$x$$w$$y$$w-dis(x,y)$$x$$x$$w-dis(x,y)=w-dep(x)-dep(y)+2*dep(lca)$$w-dep(x)$$-dep(y)$$+2*dep(lca)$$x$$+2$$\frac{n(n+1)(2n+1)}{6}$$n=1,24$$(1,k)$$(n,k)$$(n+k,k)$$(n,k)$$(nk,k)$$n,k$$1 \leq x \leq n,1 \leq y \leq k$$(x,y)$$x\%y=0/1$$n$$n$$f…</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke08&amp;rev=1596790359&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-08-07T16:52:39+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:niuke08</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke08&amp;rev=1596790359&amp;do=diff</link>
        <description>2020牛客暑期多校第八场

比赛地址

牛客OJ

Pro: 3/3/11

Rank: 55/685

[G] Game SET

题意

给出一些扑克牌,牌面上有四个属性,每种属性有三种可能的取值,还可能是通配符.问能否选出三张牌,使得它们每个属性都互不相同或者完全一样.$O(1)$$n$</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke09&amp;rev=1597390666&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-08-14T15:37:46+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:niuke09</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke09&amp;rev=1597390666&amp;do=diff</link>
        <description>2020牛客暑期多校第九场

比赛地址

牛客OJ

Pro: 5/5/12

Rank: 161/975

[A] Groundhog and 2-Power Representation

题意&amp;题解

签到题

Python大法好

[E] Groundhog Chasing Death

题意

求$\Pi_{i=a}^{b}\Pi_{j=c}^{d}Gcd(x^{i},y^{j})$

题解

先分解质因子,然后计算每个质因子的贡献.如果某个质因子是两个数共有的,就计算一下其指数在哪个范围的时候,gcd的结果取第一个数的因子,以及在哪个范围内取第二个数的因子,累计起来即可.需要卡一下常数.$n$$m$$m$$n$…</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke10&amp;rev=1597390725&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-08-14T15:38:45+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:niuke10</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:niuke10&amp;rev=1597390725&amp;do=diff</link>
        <description>2020牛客暑期多校第十场

比赛地址

牛客OJ

Pro: 3/3/10

Rank: 159/906

[A] Permutation

题意

给出一个质数$p$,要求找到一个$1$到$p-1$的排列,使得排列的后一项和前一项的两倍同余,或者和前一项的三倍同余.

题解

直接从1开始构造,先按照倍数$2$$3$</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:nwerc2019&amp;rev=1588941604&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-05-08T20:40:04+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:nwerc2019</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:nwerc2019&amp;rev=1588941604&amp;do=diff</link>
        <description>比赛地址

Codeforces Gym

题解

在写了在写了

复盘分析

在写了在写了

总结

在写了在写了</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:nwrussia2019&amp;rev=1590914011&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-05-31T16:33:31+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:nwrussia2019</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:nwrussia2019&amp;rev=1590914011&amp;do=diff</link>
        <description>比赛地址

Codeforces Gym

Pro: 8/8/13

Rank: 19/112

题解

[A] Accurate Movement

题意&amp;题解

签到题

[B] Bad Treap

题意

给出一个Treap的创建规则,其权值$y$和键值$x$的关系是$y=\sin x$.求一组数据,把这种方法构造的Treap卡成一条链.

题解
$k$$k$$2\pi$$T$$k+xT$$2\pi$$n$$a_{i}$$q$$t$$t$$\frac{n}{t}\log n$$t$$O(n \log n \log n)$$2^{i}$$n$$i$$i-1$$1$$j$$j$$i$$k$$j$$k$$k$$i$</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:paper_board&amp;rev=1595503636&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-07-23T19:27:16+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:paper_board</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:paper_board&amp;rev=1595503636&amp;do=diff</link>
        <description>2020/01/01 -- 2020/02/02 周报

团队训练

Marvolo

专题

比赛

题目

Kevin

专题

比赛

题目

TownYan

专题

比赛

题目

本周推荐

Marvolo

Kevin

TownYan</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:polynomial&amp;rev=1590239816&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-05-23T21:16:56+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:polynomial</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:polynomial&amp;rev=1590239816&amp;do=diff</link>
        <description>多项式求逆

定义

对于一个多项式$A(x)$,如果存在另一个多项式$B(x)$,有$deg  B(x) \leq deg  A(x) $,且$A(x)B(x) \equiv 1 (\mod x^{n})$,那么称$B(x)$为$A(x)$在$\mod x^{n}$下的逆元,记为$A^{-1}(x)$

求法

当$n=1$时,$A(x) \equiv c (\mod x)$,此时$A^{-1}(x) \equiv c^{-1}$

不妨设$A(x)B^{'}(x) \equiv 1 (\mod x^{\lceil \frac{n}{2} \rceil})$,$A(x)B(x) \equiv 1 (\mod x^{n})$

显然,也有$A(x)B(x) \equiv 1 (\mod x^{\lceil \frac{n}{2} \rceil})$

和第一个式子相减,可得$B(x) \equiv B^{'}(x) (\mod x^{\lceil \frac{n}{2} \rceil})$

移项,两边平方,有$B^{2}(x)-2B(x)B^{'}(x)+B^{'2}(x) \equ…</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:swerc2019&amp;rev=1590050248&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-05-21T16:37:28+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:swerc2019</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:swerc2019&amp;rev=1590050248&amp;do=diff</link>
        <description>比赛地址

Codeforces Gym

Rank: 26/65

Pro: 5/7/12

[A] Environment-Friendly Travel

题意

给出一个图,求起点到终点的所有路径中,不超过距离$b$的花费最小的路径是多少.每条路的花费和路径长度并不相同.

题解

考虑对Dijkstra进行一下改进,用$dis[i][j]$$i$$j$$s$$l$$n$$s[i]$$i$$j$$i&lt;j$$++s[j]$$i&gt;j$$i$$s$$O(ns)$$t$$t$$t$$t$$t$$t$$t$$a$$b$$t$$a$$a$$b$$b$</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:taibei2019&amp;rev=1590049686&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-05-21T16:28:06+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:taibei2019</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:taibei2019&amp;rev=1590049686&amp;do=diff</link>
        <description>比赛地址

Codeforces Gym

Rank: 14/109

Pro: 8/8/13

题解

[A] Rush Hour Puzzle

题意

给出一个$6\times 6$的棋盘,上面散布着有长度为2或3的一些玩具车.每个车为横向或者纵向放置.游戏规则和华容道比较像,问能否在10步数内将某辆车移出棋盘.$n$$1 \leq n &lt;2000$$(r-l+1)\sum_{i=l}^{r}a_{i}$$k$$-1$$x$$$1999(x-1)-1998x=k$$$x=k+1999$$x$$n$$a$$b$$\frac{1}{n}=\frac{1}{a \oplus b}+\frac{1}{b}$$b=n+1$$a$$m$$n$</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:train0806&amp;rev=1596790398&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-08-07T16:53:18+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:train0806</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:train0806&amp;rev=1596790398&amp;do=diff</link>
        <description>比赛地址

Codeforces Gym

[A] Hacker Cups and Balls

题意

给出一个排列,有一系列操作,每次会选中一段区间,将区间排序后正序或者反序放回去.求最后在最中间的元素是什么.

题解

二分答案+线段树.

二分最后的答案,将原序列中大于等于这个数的数视为1,小的视为0.排序操作就可以看做将整个区间的1全部挪到左边或者右边.线段树维护下区间和以及区间赋值操作就行了.$k$</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:training&amp;rev=1596099126&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-07-30T16:52:06+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:training</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:training&amp;rev=1596099126&amp;do=diff</link>
        <description>2019-2020 ICPC Northwestern European Regional Programming Contest (NWERC 2019)

2019-2020 ICPC Southwestern European Regional Programming Contest (SWERC 2019-2020)

2019-2020 ICPC Asia Taipei-Hsinchu Regional Contest

2019-2020 ICPC North-Western Russia Regional Contest

2020牛客暑期多校第一场

2020牛客暑期多校第二场</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_5_4-2020_5_10&amp;rev=1589094138&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-05-10T15:02:18+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:week_1_2020_5_4-2020_5_10</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_5_4-2020_5_10&amp;rev=1589094138&amp;do=diff</link>
        <description>本周推荐

Marvolo

数位DP

同类分布

AHOI2009 同类分布

先枚举各位数字之和作为模数再DP

代码



花神的数论题

花神的数论题

和上面那个差不多,枚举1的数量

代码

枚举+数位DP式的写法,状态的描述和传统的题目有一点区别

----------
$O(n^2logn)$$O(nlogn)$</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_5_11-2020_5_17&amp;rev=1590050276&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-05-21T16:37:56+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:week_1_2020_5_11-2020_5_17</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_5_11-2020_5_17&amp;rev=1590050276&amp;do=diff</link>
        <description>本周训练

2019-2020 ICPC Southwestern European Regional Programming Contest (SWERC 2019-2020)

本周推荐

Marvolo

多项式求逆和除法

多项式求逆

定义

对于一个多项式$A(x)$,如果存在另一个多项式$B(x)$,有$deg  B(x) \leq deg  A(x) $,且$A(x)B(x) \equiv 1 (\mod x^{n})$,那么称$B(x)$为$A(x)$在$\mod x^{n}$下的逆元,记为$A^{-1}(x)$

求法

当$n=1$时,$A(x) \equiv c (\mod x)$,此时$A^{-1}(x) \equiv c^{-1}$

不妨设$A(x)B^{'}(x) \equiv 1 (\mod x^{\lceil \frac{n}{2} \rceil})$,$A(x)B(x) \equiv 1 (\mod x^{n})$

显然,也有$A(x)B(x) \equiv 1 (\mod x^{\lceil \frac{n}{2} \rceil})$

和第一…</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_5_18-2020_5_24&amp;rev=1590914202&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-05-31T16:36:42+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:week_1_2020_5_18-2020_5_24</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_5_18-2020_5_24&amp;rev=1590914202&amp;do=diff</link>
        <description>本周训练

2019-2020 ICPC Asia Taipei-Hsinchu Regional Contest

Rank: 14/109

Pro: 8/8/13

本周推荐

Marvolo

这周主要完成了多项式的Wiki

多项式Wiki

Kevin

下次一定

TangYan

下次一定</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_5_25-2020_5_31&amp;rev=1590914116&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-05-31T16:35:16+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:week_1_2020_5_25-2020_5_31</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_5_25-2020_5_31&amp;rev=1590914116&amp;do=diff</link>
        <description>本周训练

2019-2020 ICPC North-Western Russia Regional Contest

Pro: 8/8/13

Rank: 19/112 

本周推荐

Marvolo

Lucas定理

若$p$是质数,则有$C_{n}^{m} \% p \equiv C_{n\%p}^{m\%p} \times C_{n/p}^{m/p} \%p$

一般$p\leq 10^{5}$的时候,通过预处理阶乘及其逆元可以递归计算.在算阶乘的逆元的时候,是可以线性计算的,原理为:$\frac{1}{(n-1)!}=\frac{n}{n!} \rightarrow inv_{(n-1)!}=n \times inv_{n!}$

模板


IL void Ready(){
    reg int i=0;
    mi[0]=inv[0]=1;
    for (i=1;i&lt;=MOD;i++)    mi[i]=(mi[i-1]*i)%MOD;
    inv[MOD-1]=Mi(MOD-1,MOD-2);
    for (i=MOD-1;i;i--) inv[i-1]…</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_6_1-2020_6_7&amp;rev=1591700902&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-06-09T19:08:22+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:week_1_2020_6_1-2020_6_7</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_6_1-2020_6_7&amp;rev=1591700902&amp;do=diff</link>
        <description>本周训练

大家的事情撞车了,然后就咕咕咕了QAQ

本周推荐

Marvolo

让我挺过DS的考试...

Kevin

下次一定

TangYan

下次一定</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_7_11-2020_7_17&amp;rev=1594980810&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-07-17T18:13:30+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:week_1_2020_7_11-2020_7_17</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_7_11-2020_7_17&amp;rev=1594980810&amp;do=diff</link>
        <description>2020/07/11 -- 2020/07/17 周报

团队训练

2020牛客暑期多校第一场

2020牛客暑期多校第二场

Marvolo

专题

动态点分治

比赛

Atcoder AIsing Programming Contest 2020

题目

[ZJOI2007 捉迷藏]

Kevin

专题

图论杂项

比赛

无

题目

见本周推荐

TownYan

专题

无

比赛

Atcoder AIsing Programming Contest 2020

题目

见本周推荐

本周推荐

Marvolo
$N$$M$$1e5$$1$$N$$1$$N$$1$$N$$x$$O(kN+M)$$k$</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_7_18-2020_7_24&amp;rev=1595583046&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-07-24T17:30:46+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:week_1_2020_7_18-2020_7_24</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_7_18-2020_7_24&amp;rev=1595583046&amp;do=diff</link>
        <description>2020/07/18 -- 2020/07/24 周报

团队训练

2020牛客暑期多校第三场

2020牛客暑期多校第四场

7.23训练

Marvolo

专题

Min_25筛(式子有点多,正在研究)

比赛

这周训练比较密集,比赛摸了

题目

CF的几道题:

Prefix Flip

 Create The Teams

Omkar and Baseball

Kevin

专题

图论

比赛

无

题目

 LeetCode 212.

见下方本周推荐$2n$</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_7_25-2020_7_31&amp;rev=1596187749&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-07-31T17:29:09+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:week_1_2020_7_25-2020_7_31</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_7_25-2020_7_31&amp;rev=1596187749&amp;do=diff</link>
        <description>2020/01/01 -- 2020/02/02 周报

团队训练

2020牛客暑期多校第五场

2020牛客暑期多校第六场

Marvolo

专题

无

比赛

Codeforces: Educational Codeforces Round 92

AtCoder: M-SOLUTIONS Programming Contest 2020

题目

AtCoder:

Air Safety

具体见本周推荐.

Kevin

专题

无

比赛

Codeforces: Educational Codeforces Round 92

题目

LeetCode 4.

具体见本周推荐

TownYan

专题

无

比赛
$A, B$$\log$$k=\lfloor\frac{m+n+1}{2}\rfloor$$A$$p$$p = \max\{p \mid B[k-p] \le A[p]\ \text{and}\ B[k-p+1] \ge A[p]\}$$B$$p$$\log$…</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_8_1-2020_8_7&amp;rev=1596790879&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-08-07T17:01:19+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:week_1_2020_8_1-2020_8_7</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_8_1-2020_8_7&amp;rev=1596790879&amp;do=diff</link>
        <description>2020/08/01 -- 2020/08/07 周报

团队训练

2020牛客暑期多校第七场

2020牛客暑期多校第八场

08.06训练

Marvolo

专题

动态图连通性

比赛

AtCoder Beginner Contest 174

题目

LOJ:

分拆数

「离线可过」动态图连通性

Kevin

专题

贪心乱搞

比赛

暂无

题目

见本周推荐

TownYan

专题

暂无

比赛

暂无

题目

见本周推荐$f(i)$$i$$f(1)$$f(n)$$\Pi \frac{1}{1-x^{i}}$$ln$$\sum \sum \frac{x^{i*j}}{j}$$O(n \log n)$$O(n \log n)$$s$$k$$\le$$+k$$+k$$\ge$$n^2$$l=0, r=1$$s[l:r]$$\text{ans}=\max\{\text{ans},~r-l\}$$r+=1$$s[l:r]$$s[l:r]$$\forall t \in [r, len(s)],~s[l:t]$$l$$l+=1,~r+=1$$l+1$…</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_8_8-2020_8_14&amp;rev=1597401949&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-08-14T18:45:49+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:week_1_2020_8_8-2020_8_14</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_8_8-2020_8_14&amp;rev=1597401949&amp;do=diff</link>
        <description>2020/08/08 -- 2020/08/14 周报

团队训练

2020牛客暑期多校第九场

2020牛客暑期多校第十场

Marvolo

专题

无

比赛

AtCoder Grand Contest 047

题目

见本周推荐

Kevin

专题

无

比赛

无

题目

见本周推荐

TownYan

专题

无

比赛

无

题目

见本周推荐

本周推荐

Marvolo

AtCoder:$x$$y$$x'$$y'$$x+x' \geq 0$$y+y' \geq 0$$[L, R]$$\le 10^9$$\text{n}$$b_{n} b_{n-1} \cdots b_2 b_1$$\exists \ p \in [1, n]，s.t. \sum\limits_{i\ =\ len}^{1}\{b_i\times (i-p) \} = 0$$\in [1, len]$…</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_8_15-2020_8_21&amp;rev=1598002147&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-08-21T17:29:07+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:week_1_2020_8_15-2020_8_21</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_8_15-2020_8_21&amp;rev=1598002147&amp;do=diff</link>
        <description>2020/08/15 -- 2020/08/21 周报

团队训练

无

Marvolo

专题

无

比赛

AtCoder Beginner Contest 175

Codeforces Global Round 10 

题目

Codeforces:

Omkar and Duck

具体见本周推荐

Kevin

专题

无

比赛

无

题目

下次一定

TownYan

专题

无

比赛

无

题目

见本周推荐

本周推荐
$n*n$$10^{16}$$2^{50}&lt;10^{16}$$(i,j)$$2^{i+j}$$n \leq 25$</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_8_22-2020_8_28&amp;rev=1598604712&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-08-28T16:51:52+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:week_1_2020_8_22-2020_8_28</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_8_22-2020_8_28&amp;rev=1598604712&amp;do=diff</link>
        <description>2020/01/01 -- 2020/02/02 周报

团队训练

无

Marvolo

专题

无

比赛

Codeforces Round #665 (Div. 2)

题目

见本周推荐

Kevin

专题

比赛

题目

TownYan

专题

无

比赛

无

题目

见本周推荐

本周推荐

Marvolo

Codeforces:

Divide Square

题意:

给出一个边长为$1e6$$x$$x$$\text{A, T, C, G}$$m\in[1, 10]$$\in [1, 10]$$n\in[0, 2\times 10^9]$$n$$m$$10000$$n$$m$$m$$\text{trie}$$n$$\text{fail}$$\text{trie}$$\text{trie}$$=\Sigma len_i\le 100$$\text{O}(~(\Sigma len_i)^3 \log{n}~)$…</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_8_29-2020_9_04&amp;rev=1599209926&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-09-04T16:58:46+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:week_1_2020_8_29-2020_9_04</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:week_1_2020_8_29-2020_9_04&amp;rev=1599209926&amp;do=diff</link>
        <description>2020/01/01 -- 2020/02/02 周报

团队训练

无

Marvolo

专题

无

比赛

AtCoder Beginner Contest 177

题目

见本周推荐

Kevin

专题

无

比赛

无

题目

无

TownYan

专题

无

比赛

AtCoder Beginner Contest 177

题目

无

本周推荐

Marvolo

AtCoder:

I hate Shortest Path Problem

题意:

给出一个$n*m$$i$$[l,r]$$[1,l-1],[r+1,m]$$[l,r]$$r+1$$ans_{i}-i$$r+1$$r+1$</description>
    </item>
    <item rdf:about="https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:wiki_board&amp;rev=1588941575&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2020-05-08T20:39:35+0800</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>2020-2021:teams:tle233:wiki_board</title>
        <link>https://wiki.cvbbacm.com/doku.php?id=2020-2021:teams:tle233:wiki_board&amp;rev=1588941575&amp;do=diff</link>
        <description>比赛模板

周报模板</description>
    </item>
</rdf:RDF>
